Mohali test: India bundle out Australia for 192, need 216 for win
October 4th, 2010 - 6:11 pm ICT by IANS
Mohali (Punjab), Oct 4 (IANS) India bundled out Australia for 192 runs in their second innings on the fourth day of the first test match at the Punjab Cricket Association (PCA) stadium here Monday.
India have a target of 216 runs — as Australia had a 23-run lead in the first innings — to win the test which ends Tuesday.
Pacer Ishant Sharma triggered the Australian collapse in the second half of the pre-lunch session, getting three top wickets within a span of eight balls.
Speedster Zaheer Khan bagged three wickets while spinners Harbhajan Singh and Pragyan Ojha got two wickets each in the post-lunch session.
Shane Watson (56), Simon Katich (37) and Michael Hussey (28) were the only batsmen to show some resistance to the Indian bowling. The only other batsman to get into double figures was Marcus North (10).
Watson gave a good start to the Australian innings Monday morning, smashing 56 runs off 59 balls (7 fours, one six). At one stage, Australia were 87 runs without any loss.
However, they collapsed with the innings lasting only 60.5 overs.
Australia scored 428 runs in the first innings. India replied with 405 runs.
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Tags: batsman, collapse, eight balls, first test, harbhajan singh, indian bowling, lunch session, michael hussey, ojha, pacer, pca stadium, pragyan, punjab cricket association, shane watson, simon katich, stage australia, target, test match, wickets, zaheer khan